jee-main 2002 Q8
Equilibrium force removal
When forces $F_1, F_2, F_3$ are acting on a particle of mass $m$ such that $F_2$ and $F_3$ are mutually perpendicular, then the particle remains stationary. If the force $F_1$ is now removed then the acceleration of the particle is
(1) $\mathrm{F}_1 / \mathrm{m}$
(2) $\mathrm{F}_2 \mathrm{~F}_3 / \mathrm{mF}_1$
(3) $\left(F_2 - F_3\right) / m$
(4) $\mathrm{F}_2 / \mathrm{m}$