Show that a geometric sequence is hypergeometric.

Suppose four distinct positive numbers $a _ { 1 } , a _ { 2 } , a _ { 3 } , a _ { 4 }$ are in G.P. Let $b _ { 1 } = a _ { 1 }$, $b _ { 2 } = b _ { 1 } + a _ { 2 } , b _ { 3 } = b _ { 2 } + a _ { 3 }$ and $b _ { 4 } = b _ { 3 } + a _ { 4 }$. STATEMENT-1 : The numbers $b _ { 1 } , b _ { 2 } , b _ { 3 } , b _ { 4 }$ are neither in A.P. nor in G.P. and
STATEMENT-2 : The numbers $b _ { 1 } , b _ { 2 } , b _ { 3 } , b _ { 4 }$ are in H.P.
(A) STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for STATEMENT-1
(B) STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1
(C) STATEMENT-1 is True, STATEMENT-2 is False
(D) STATEMENT-1 is False, STATEMENT-2 is True

Let $a , b , c , d$ and $p$ be non-zero distinct real numbers such that $\left( a ^ { 2 } + b ^ { 2 } + c ^ { 2 } \right) p ^ { 2 } - 2 ( a b + b c + c d ) p + \left( b ^ { 2 } + c ^ { 2 } + d ^ { 2 } \right) = 0$. Then
(1) $a , b , c$ are in A.P.
(2) $a , c , p$ are in G.P.
(3) $a , b , c , d$ are in G.P.
(4) $a , b , c , d$ are in A.P.

If three successive terms of a G.P. with common ratio $r$ ($r > 1$) are the lengths of the sides of a triangle and $[r]$ denotes the greatest integer less than or equal to $r$, then $3[r] + [-r]$ is equal to: