If $\int f(x)\, dx = \psi(x)$, then $\int x^5 f\left(x^3\right) dx$, is equal to
(1) $\frac{1}{3}x^3 \psi\left(x^3\right) - \int x^2 \psi\left(x^3\right) dx + c$
(2) $\frac{1}{3}\left[x^3 \psi\left(x^3\right) - \int x^3 \psi\left(x^3\right) dx\right] + c$
(3) $\frac{1}{3}\left[x^3 \psi\left(x^3\right) - \int x^2 \psi\left(x^3\right) dx\right] + c$
(4) $\frac{1}{3}x^3 \psi\left(x^3\right) - 3\int x^3 \psi\left(x^3\right) dx + c$