LFM Stats And Pure

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jee-main 2023 Q71 Counting Functions with Constraints View
Let $A = \{2, 3, 4\}$ and $B = \{8, 9, 12\}$. Then the number of elements in the relation $R = \{ ( ( a _ { 1 } , b _ { 1 } ) , ( a _ { 2 } , b _ { 2 } ) ) \in ( A \times B ) \times ( A \times B ) : a _ { 1 }$ divides $b _ { 2 }$ and $a _ { 2 }$ divides $b _ { 1 } \}$ is
(1) 36
(2) 24
(3) 18
(4) 12
jee-main 2023 Q81 Word Permutations with Repeated Letters View
The number of words, with or without meaning, that can be formed using all the letters of the word ASSASSINATION so that the vowels occur together, is $\_\_\_\_$.
jee-main 2023 Q81 Dictionary Order / Rank of a Permutation View
Let 5 digit numbers be constructed using the digits $0, 2, 3, 4, 7, 9$ with repetition allowed, and are arranged in ascending order with serial numbers. Then the serial number of the number 42923 is $\underline{\hspace{1cm}}$.
jee-main 2023 Q82 Linear Arrangement with Constraints View
The number of permutations, of the digits $1, 2, 3, \ldots, 7$ without repetition, which neither contain the string 153 nor the string 2467, is $\_\_\_\_$.
jee-main 2023 Q83 Forming Numbers with Digit Constraints View
Number of 4-digit numbers that are less than or equal to 2800 and either divisible by 3 or by 11, is equal to $\underline{\hspace{1cm}}$.
jee-main 2024 Q62 Distribution of Objects into Bins/Groups View
Number of ways of arranging 8 identical books into 4 identical shelves where any number of shelves may remain empty is equal to
(1) 18
(2) 16
(3) 12
(4) 15
jee-main 2024 Q62 Dictionary Order / Rank of a Permutation View
60 words can be made using all the letters of the word BHBJO, with or without meaning. If these words are written as in a dictionary, then the $50 ^ { \text {th} }$ word is :
(1) JBBOH
(2) OBBJH
(3) OBBHJ
(4) HBBJO
jee-main 2024 Q63 Dictionary Order / Rank of a Permutation View
If all the words with or without meaning made using all the letters of the word "NAGPUR" are arranged as in a dictionary, then the word at $315 ^ { \text {th} }$ position in this arrangement is:
(1) NRAGUP
(2) NRAPUG
(3) NRAPGU
(4) NRAGPU
jee-main 2024 Q69 Counting Functions with Constraints View
Let $[ t ]$ be the greatest integer less than or equal to $t$. Let $A$ be the set of all prime factors of 2310 and $f : A \rightarrow \mathbb { Z }$ be the function $f ( x ) = \left[ \log _ { 2 } \left( x ^ { 2 } + \left[ \frac { x ^ { 3 } } { 5 } \right] \right) \right]$. The number of one-to-one functions from $A$ to the range of $f$ is
(1) 25
(2) 24
(3) 20
(4) 120
jee-main 2024 Q81 Forming Numbers with Digit Constraints View
The number of 3-digit numbers, formed using the digits $2,3,4,5$ and 7, when the repetition of digits is not allowed, and which are not divisible by 3, is equal to $\_\_\_\_$
jee-main 2024 Q81 Forming Numbers with Digit Constraints View
The number of integers, between 100 and 1000 having the sum of their digits equals to 14, is $\_\_\_\_$
jee-main 2024 Q82 Dictionary Order / Rank of a Permutation View
All the letters of the word $G T W E N T Y$ are written in all possible ways with or without meaning and these words are written as in a dictionary. The serial number of the word $G T W E N T Y$ IS
jee-main 2025 Q2 Linear Arrangement with Constraints View
In a group of 3 girls and 4 boys, there are two boys $B _ { 1 }$ and $B _ { 2 }$. The number of ways, in which these girls and boys can stand in a queue such that all the girls stand together, all the boys stand together, but $B _ { 1 }$ and $B _ { 2 }$ are not adjacent to each other, is :
(1) 96
(2) 144
(3) 120
(4) 72
jee-main 2025 Q6 Probability via Permutation Counting View
Let S be the set of all the words that can be formed by arranging all the letters of the word GARDEN. From the set S, one word is selected at random. The probability that the selected word will NOT have vowels in alphabetical order is :
(1) $\frac { 1 } { 2 }$
(2) $\frac { 1 } { 4 }$
(3) $\frac { 2 } { 3 }$
(4) $\frac { 1 } { 3 }$
jee-main 2025 Q6 Forming Numbers with Digit Constraints View
Let P be the set of seven digit numbers with sum of their digits equal to 11. If the numbers in P are formed by using the digits 1, 2 and 3 only, then the number of elements in the set $P$ is:
(1) 173
(2) 164
(3) 158
(4) 161
jee-main 2025 Q7 Dictionary Order / Rank of a Permutation View
If all the words with or without meaning made using all the letters of the word ``KANPUR'' are arranged as in a dictionary, then the word at $440 ^ { \text {th} }$ position in this arrangement, is :
(1) PRNAUK
(2) PRKANU
(3) PRKAUN
(4) PRNAKU
jee-main 2025 Q13 Word Permutations with Repeated Letters View
The number of words, which can be formed using all the letters of the word ``DAUGHTER'', so that all the vowels never come together, is
(1) 36000
(2) 37000
(3) 34000
(4) 35000
jee-main 2025 Q19 Forming Numbers with Digit Constraints View
The number of different 5 digit numbers greater than 50000 that can be formed using the digits $0, 1, 2, 3, 4, 5, 6, 7$, such that the sum of their first and last digits should not be more than 8, is
(1) 4608
(2) 5720
(3) 5719
(4) 4607
jee-main 2025 Q22 Forming Numbers with Digit Constraints View
The number of natural numbers, between 212 and 999, such that the sum of their digits is 15, is
jee-main 2025 Q23 Linear Arrangement with Constraints View
The number of ways, 5 boys and 4 girls can sit in a row so that either all the boys sit together or no two boys sit together, is
jee-main 2025 Q23 Word Permutations with Repeated Letters View
The number of 6-letter words, with or without meaning, that can be formed using the letters of the word MATHS such that any letter that appears in the word must appear at least twice, is \_\_\_\_ .
jee-main 2025 Q24 Counting Functions with Constraints View
Number of functions $f : \{1, 2, \ldots, 100\} \rightarrow \{0, 1\}$, that assign 1 to exactly one of the positive integers less than or equal to 98, is equal to $\_\_\_\_$.
kyotsu-test 2010 QCourse1-II-Q1 Forming Numbers with Digit Constraints View
Q1 Using the five numerals $0,1,2,3,4$, we are to make four-digit integers. (Note that "0123", etc. are not allowed.)
(1) The total possible number of integers where the digits are all different numerals is $\mathbf{AB}$. Among them, the total number of integers that do not use 0 is $\mathbf{CD}$.
(2) If we are allowed to use the same numeral repeatedly, then the total possible number of four-digit integers is $\mathbf{EFG}$. Among them
(i) the total number of integers that use both 1 and 3 twice is $\mathbf{H}$,
(ii) the total number of integers that use both 0 and 4 twice is $\mathbf{I}$,
(iii) the total number of integers that use both of two numerals twice is $\mathbf{JK}$.
kyotsu-test 2014 QCourse1-II-Q1 Word Permutations with Repeated Letters View
Consider the permutations of the eight letters of the word ``POSITION''.
(1) The number of permutations in which the two I's are adjacent and the two O's also are adjacent is $\mathbf { A B C }$.
(2) The number of permutations such that the permutations both begin and end with the letter I and furthermore the two O's are adjacent is $\mathbf{DEF}$.
(3) The number of permutations that both begin and end with the letter I is $\mathbf{GHI}$.
(4) The number of permutations of the 4 letters I, I, O, O is $\mathbf { J }$. Also, the number of permutations of the 4 letters $\mathrm { N } , \mathrm { P } , \mathrm { S } , \mathrm { T }$ is $\mathbf { K L }$.
Hence the number of permutations of POSITION which begin or end with either I or O, and furthermore in which none of letters $\mathrm { N } , \mathrm { P } , \mathrm { S } , \mathrm { T }$ are adjacent to each other is $\mathbf{MNO}$.
kyotsu-test 2017 QCourse1-I-Q2 Selection and Task Assignment View
We have four white cards, three red cards and three black cards. A different number is written on each of the ten cards.
(1) Choose two of the ten cards and put one in box A, and one in box B. There are $\mathbf{NO}$ ways of putting two cards in the two boxes.
(2) There are $\mathbf { P Q }$ ways of choosing two cards of the same color, and $\mathbf { R S }$ ways of choosing two cards of different colors.
Next, put the ten cards in a box and take out one card and without returning it to the box, take out second card.
(3) The probability that the two cards taken out have the same color is $\square\mathbf{ T UV}$
(4) The probability that the color of the first card taken out is white or red, and the color of the second card taken out is red or black is $\frac { \mathbf { W X } } { \mathbf { Y } \mathbf { Y } }$.