We fix a $\mathbb{C}$-vector space $E$ of dimension $n \geqslant 2$. Let $\mathcal{A}$ be an irreducible subalgebra of $\mathcal{L}(E)$ (i.e., the only vector subspaces stable by all elements of $\mathcal{A}$ are $\{0\}$ and $E$). Let $v \in \mathcal{A}$ of rank greater than or equal to 2. Show that there exists $u \in \mathcal{A}$ and $\lambda \in \mathbb{C}$ such that $$0 < \operatorname{rg}(v \circ u \circ v - \lambda v) < \operatorname{rg} v.$$ Consider $x$ and $y$ in $E$ such that the family $(v(x), v(y))$ is free, justify the existence of $u \in \mathcal{A}$ such that $u \circ v(x) = y$ and consider the endomorphism induced by $v \circ u$ on $\operatorname{Im} v$.
We fix a $\mathbb{C}$-vector space $E$ of dimension $n \geqslant 2$. Let $\mathcal{A}$ be an irreducible subalgebra of $\mathcal{L}(E)$ (i.e., the only vector subspaces stable by all elements of $\mathcal{A}$ are $\{0\}$ and $E$).
Let $v \in \mathcal{A}$ of rank greater than or equal to 2. Show that there exists $u \in \mathcal{A}$ and $\lambda \in \mathbb{C}$ such that
$$0 < \operatorname{rg}(v \circ u \circ v - \lambda v) < \operatorname{rg} v.$$
Consider $x$ and $y$ in $E$ such that the family $(v(x), v(y))$ is free, justify the existence of $u \in \mathcal{A}$ such that $u \circ v(x) = y$ and consider the endomorphism induced by $v \circ u$ on $\operatorname{Im} v$.