jee-advanced 2009 Q20

jee-advanced · India · paper2 Arithmetic Sequences and Series Summation of Derived Sequence from AP

If the sum of first $n$ terms of an A.P. is $cn^{2}$, then the sum of squares of these $n$ terms is
(A) $\frac{n\left(4n^{2}-1\right)c^{2}}{6}$
(B) $\frac{n\left(4n^{2}+1\right)c^{2}}{3}$
(C) $\frac{n\left(4n^{2}-1\right)c^{2}}{3}$
(D) $\frac{n\left(4n^{2}+1\right)c^{2}}{6}$

If the sum of first $n$ terms of an A.P. is $cn^{2}$, then the sum of squares of these $n$ terms is\\
(A) $\frac{n\left(4n^{2}-1\right)c^{2}}{6}$\\
(B) $\frac{n\left(4n^{2}+1\right)c^{2}}{3}$\\
(C) $\frac{n\left(4n^{2}-1\right)c^{2}}{3}$\\
(D) $\frac{n\left(4n^{2}+1\right)c^{2}}{6}$

Paper Questions

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