jee-main 2024 Q22

jee-main · India · session1_01feb_shift1 Not Maths
The identical spheres each of mass $2M$ are placed at the corners of a right angled triangle with mutually perpendicular sides equal to 4 m each. Taking point of intersection of these two sides as origin, the magnitude of position vector of the centre of mass of the system is $\frac { 4 \sqrt { 2 } } { x }$, where the value of $x$ is $\_\_\_\_$.
The identical spheres each of mass $2M$ are placed at the corners of a right angled triangle with mutually perpendicular sides equal to 4 m each. Taking point of intersection of these two sides as origin, the magnitude of position vector of the centre of mass of the system is $\frac { 4 \sqrt { 2 } } { x }$, where the value of $x$ is $\_\_\_\_$.