\section*{8. B}
Solution: Let the probabilities of events A, B, C, D be $P ( a ) , P ( b ) , P ( c ) , P ( d )$ respectively. Then $P ( a ) = \frac { 1 } { 6 } , P ( b ) = \frac { 5 } { 36 } , P ( d ) = \frac { 1 } { 36 }$. The probability that A and C occur simultaneously is $P ( a c ) = 0$; the probability that A and D occur simultaneously is $P ( a d ) = 0$; the probability that B and C occur simultaneously is $P ( b c ) = \frac { 1 } { 36 }$; the probability that C and D occur simultaneously is $P ( c d ) = 0$. The condition $P ( x y ) = P ( x ) P ( y )$ is satisfied by option B.

\section*{II. Multiple Selection Questions}