cmi-entrance 2013 QB1

cmi-entrance · India · ugmath 15 marks Sine and Cosine Rules Multi-step composite figure problem
In triangle $ABC$, the bisector of angle $A$ meets side $BC$ in point $D$ and the bisector of angle $B$ meets side $AC$ in point $E$. Given that $DE$ is parallel to $AB$, show that $\mathrm{AE} = \mathrm{BD}$ and that the triangle $ABC$ is isosceles.
In triangle $ABC$, the bisector of angle $A$ meets side $BC$ in point $D$ and the bisector of angle $B$ meets side $AC$ in point $E$. Given that $DE$ is parallel to $AB$, show that $\mathrm{AE} = \mathrm{BD}$ and that the triangle $ABC$ is isosceles.