jee-advanced 2014 Q49

jee-advanced · India · paper1 Circles Circle Equation Derivation
A circle $S$ passes through the point $(0,1)$ and is orthogonal to the circles $(x-1)^2 + y^2 = 16$ and $x^2 + y^2 = 1$. Then
(A) radius of $S$ is 8
(B) radius of $S$ is 7
(C) centre of $S$ is $(-7, 1)$
(D) centre of $S$ is $(-8, 1)$
A circle $S$ passes through the point $(0,1)$ and is orthogonal to the circles $(x-1)^2 + y^2 = 16$ and $x^2 + y^2 = 1$. Then\\
(A) radius of $S$ is 8\\
(B) radius of $S$ is 7\\
(C) centre of $S$ is $(-7, 1)$\\
(D) centre of $S$ is $(-8, 1)$