jee-advanced 2016 Q46

jee-advanced · India · paper1 Differential equations Solving Separable DEs with Initial Conditions

A solution curve of the differential equation $\left(x^2 + xy + 4x + 2y + 4\right)\frac{dy}{dx} - y^2 = 0, x > 0$, passes through the point $(1,3)$. Then the solution curve
(A) intersects $y = x + 2$ exactly at one point
(B) intersects $y = x + 2$ exactly at two points
(C) intersects $y = (x+2)^2$
(D) does NOT intersect $y = (x+3)^2$

A solution curve of the differential equation $\left(x^2 + xy + 4x + 2y + 4\right)\frac{dy}{dx} - y^2 = 0, x > 0$, passes through the point $(1,3)$. Then the solution curve\\
(A) intersects $y = x + 2$ exactly at one point\\
(B) intersects $y = x + 2$ exactly at two points\\
(C) intersects $y = (x+2)^2$\\
(D) does NOT intersect $y = (x+3)^2$

Paper Questions

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