jee-main 2013 Q74

jee-main · India · 07apr Differentiation from First Principles

The value of $\lim_{x \rightarrow 0} \frac{(1 - \cos 2x)(3 + \cos x)}{x \tan 4x}$ is equal to
(1) 1
(2) 2
(3) $-\frac{1}{4}$
(4) $\frac{1}{2}$

The value of $\lim_{x \rightarrow 0} \frac{(1 - \cos 2x)(3 + \cos x)}{x \tan 4x}$ is equal to\\
(1) 1\\
(2) 2\\
(3) $-\frac{1}{4}$\\
(4) $\frac{1}{2}$

Paper Questions

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