Let $f ( x ) = x ^ { 2 } + \frac { 1 } { x ^ { 2 } }$ and $g ( x ) = x - \frac { 1 } { x } , x \in R - \{ - 1,0,1 \}$. If $h ( x ) = \frac { f ( x ) } { g ( x ) }$, then the local minimum value of $h ( x )$ is:\\
(1) $2 \sqrt { 2 }$\\
(2) 3\\
(3) - 3\\
(4) $- 2 \sqrt { 2 }$