jee-main 2022 Q79

jee-main · India · session1_27jun_shift2 Vectors: Lines & Planes Distance Computation (Point-to-Plane or Line-to-Line)

The shortest distance between the lines $\frac { x - 3 } { 2 } = \frac { y - 2 } { 3 } = \frac { z - 1 } { - 1 }$ and $\frac { x + 3 } { 2 } = \frac { y - 6 } { 1 } = \frac { z - 5 } { 3 }$ is
(1) $\frac { 18 } { \sqrt { 5 } }$
(2) $\frac { 22 } { 3 \sqrt { 5 } }$
(3) $\frac { 46 } { 3 \sqrt { 5 } }$
(4) $6 \sqrt { 3 }$

The shortest distance between the lines $\frac { x - 3 } { 2 } = \frac { y - 2 } { 3 } = \frac { z - 1 } { - 1 }$ and $\frac { x + 3 } { 2 } = \frac { y - 6 } { 1 } = \frac { z - 5 } { 3 }$ is\\
(1) $\frac { 18 } { \sqrt { 5 } }$\\
(2) $\frac { 22 } { 3 \sqrt { 5 } }$\\
(3) $\frac { 46 } { 3 \sqrt { 5 } }$\\
(4) $6 \sqrt { 3 }$

Paper Questions

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