For this question write your answers as a series of four letters (Y for Yes and N for No) in order. Is it possible to find a $2 \times 2$ matrix $M$ for which the equation $M\vec{x} = \vec{p}$ has: (a) no solutions for some but not all $\vec{p}$; exactly one solution for all other $\vec{p}$? (b) exactly one solution for some but not all $\vec{p}$; more than one solution for all other $\vec{p}$? (c) no solutions for some but not all $\vec{p}$; more than one solution for all other $\vec{p}$? (d) no solutions for some $\vec{p}$, exactly one solution for some $\vec{p}$ and more than one solution for some $\vec{p}$?
For this question write your answers as a series of four letters (Y for Yes and N for No) in order. Is it possible to find a $2 \times 2$ matrix $M$ for which the equation $M\vec{x} = \vec{p}$ has:\\
(a) no solutions for some but not all $\vec{p}$; exactly one solution for all other $\vec{p}$?\\
(b) exactly one solution for some but not all $\vec{p}$; more than one solution for all other $\vec{p}$?\\
(c) no solutions for some but not all $\vec{p}$; more than one solution for all other $\vec{p}$?\\
(d) no solutions for some $\vec{p}$, exactly one solution for some $\vec{p}$ and more than one solution for some $\vec{p}$?