jee-main 2024 Q81

jee-main · India · session1_30jan_shift2 Sign Change & Interval Methods
The number of real solutions of the equation $x\left(x^2 + 3|x| + 5|x-1| + 6|x-2|\right) = 0$ is $\underline{\hspace{1cm}}$.
The number of real solutions of the equation $x\left(x^2 + 3|x| + 5|x-1| + 6|x-2|\right) = 0$ is $\underline{\hspace{1cm}}$.