$x = \sqrt[3]{4}$ $$y = \sqrt[4]{8}$$ $$z = \sqrt[5]{16}$$ Given that, which of the following orderings is correct? A) $x < y < z$ B) $x < z < y$ C) $y < x < z$ D) $z < x < y$ E) $z < y < x$
$x = \sqrt[3]{4}$
$$y = \sqrt[4]{8}$$
$$z = \sqrt[5]{16}$$
Given that, which of the following orderings is correct?
A) $x < y < z$
B) $x < z < y$
C) $y < x < z$
D) $z < x < y$
E) $z < y < x$