gaokao 2010 Q1

gaokao · China · shanghai-science Inequalities Solve Polynomial/Rational Inequality for Solution Set

1. The solution set of the inequality $\frac { 2 - x } { x + 4 } > 0$ is $\_\_\_\_$ $( - 4,2 )$.
Analysis: This examines the method for solving fractional inequalities. $\frac { 2 - x } { x + 4 } > 0$ is equivalent to $( x - 2 ) ( x + 4 ) < 0$, so $- 4 < x < 2$

(5 points) Given sets $A = \{ x | | x | \leqslant 2 , x \in \mathbb{R} \} , B = \{ x \mid \sqrt { x } \leqslant 4 , x \in \mathbb{Z} \}$, then $A \cap B =$

1. The solution set of the inequality $\frac { 2 - x } { x + 4 } > 0$ is $\_\_\_\_$ $( - 4,2 )$.

Analysis: This examines the method for solving fractional inequalities. $\frac { 2 - x } { x + 4 } > 0$ is equivalent to $( x - 2 ) ( x + 4 ) < 0$, so $- 4 < x < 2$\\

Paper Questions

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