124- What is $\displaystyle\int_{\frac{\pi}{4}}^{\frac{\pi}{2}} \dfrac{1 + \cos 2x}{2\sin^2 x}\, dx$?
(1) $1 - \sqrt{2}$ (2) $1 - \dfrac{\pi}{4}$ (3) $\dfrac{\pi}{2} - 1$ (4) $\dfrac{2}{4}$
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\textbf{124-} What is $\displaystyle\int_{\frac{\pi}{4}}^{\frac{\pi}{2}} \dfrac{1 + \cos 2x}{2\sin^2 x}\, dx$?

\hspace*{2cm} (1) $1 - \sqrt{2}$ \hspace{2cm} (2) $1 - \dfrac{\pi}{4}$ \hspace{2cm} (3) $\dfrac{\pi}{2} - 1$ \hspace{2cm} (4) $\dfrac{2}{4}$



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\textbf{Mathematics \hfill 120-C \hfill Page 5}

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