Q90. In a tournament, a team plays 10 matches with probabilities of winning and losing each match as $\frac { 1 } { 3 }$ and $\frac { 2 } { 3 }$ respectively. Let $x$ be the number of matches that the team wins, and $y$ be the number of matches that team loses. If the probability $\mathrm { P } ( | x - y | \leq 2 )$ is $p$, then $3 ^ { 9 } p$ equals $\_\_\_\_$
Q90. In a tournament, a team plays 10 matches with probabilities of winning and losing each match as $\frac { 1 } { 3 }$ and $\frac { 2 } { 3 }$ respectively. Let $x$ be the number of matches that the team wins, and $y$ be the number of matches that team loses. If the probability $\mathrm { P } ( | x - y | \leq 2 )$ is $p$, then $3 ^ { 9 } p$ equals $\_\_\_\_$
\section*{ANSWER KEYS}
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1. (3) & 2. (1) & 3. (4) \\
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9. (2) & 10. (1) & 11. (1) \\
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17. (3) & 18. (4) & 19. (4) \\
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25. (750) & 26. (32) & 27. (5) \\
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33. (4) & 34. (2) & 35. (4) \\
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