jee-main 2025 Q90

jee-main · India · session2_08apr_shift2 Vectors 3D & Lines Distance from a Point to a Line (Show/Compute)
Q90. The square of the distance of the image of the point $( 6,1,5 )$ in the line $\frac { x - 1 } { 3 } = \frac { y } { 2 } = \frac { z - 2 } { 4 }$, from the origin is
ANSWER KEYS

\begin{tabular}{|l|l|l|l|} \hline 1. (1) & 2. (2) & 3. (1) & 4. (4) \hline 9. (1) & 10. (1) & 11. (1) & 12. (2) \hline 17. (4) & 18. (1) & 19. (2) & 20. (2) \hline 25. (22) & 26. (16) & 27. (2500) & 28. (28) \hline 33. (1) & 34. (2) & 35. (2) & 36. (4) \hline 41. (4) & 42. (1) & 43. (1) & 44. (3) \hline
Q90. The square of the distance of the image of the point $( 6,1,5 )$ in the line $\frac { x - 1 } { 3 } = \frac { y } { 2 } = \frac { z - 2 } { 4 }$, from the origin is

\section*{ANSWER KEYS}
\begin{center}
\begin{tabular}{|l|l|l|l|}
\hline
1. (1) & 2. (2) & 3. (1) & 4. (4) \\
\hline
9. (1) & 10. (1) & 11. (1) & 12. (2) \\
\hline
17. (4) & 18. (1) & 19. (2) & 20. (2) \\
\hline
25. (22) & 26. (16) & 27. (2500) & 28. (28) \\
\hline
33. (1) & 34. (2) & 35. (2) & 36. (4) \\
\hline
41. (4) & 42. (1) & 43. (1) & 44. (3) \\
\hline