The circles with equations
$$\begin{aligned}
&(x+4)^2 + (y+1)^2 = 64 \quad \text{and} \\
&(x-8)^2 + (y-4)^2 = r^2 \quad \text{where } r > 0
\end{aligned}$$
have exactly one point in common.
Find the difference between the two possible values of $r$.