tmua 2020 Q9

tmua · Uk · paper1 1 marks Solving quadratics and applications Finding roots or coefficients of a quadratic using Vieta's relations

The quadratic expression $x^2 - 14x + 9$ factorises as $(x - \alpha)(x - \beta)$, where $\alpha$ and $\beta$ are positive real numbers.
Which quadratic expression can be factorised as $(x - \sqrt{\alpha})(x - \sqrt{\beta})$?
A $x^2 - \sqrt{10}x + 3$
B $x^2 - \sqrt{14}x + 3$
C $x^2 - \sqrt{20}x + 3$
D $x^2 - 178x + 81$
E $x^2 - 176x + 81$
F $x^2 + 196x + 81$

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The quadratic expression $x^2 - 14x + 9$ factorises as $(x - \alpha)(x - \beta)$, where $\alpha$ and $\beta$ are positive real numbers.

Which quadratic expression can be factorised as $(x - \sqrt{\alpha})(x - \sqrt{\beta})$?

A $x^2 - \sqrt{10}x + 3$

B $x^2 - \sqrt{14}x + 3$

C $x^2 - \sqrt{20}x + 3$

D $x^2 - 178x + 81$

E $x^2 - 176x + 81$

F $x^2 + 196x + 81$

Paper Questions

Q1 Q2 Q3 Q4 Q5 Q6 Q7 Q8 Q9 Q10 Q11 Q12 Q13 Q14 Q15 Q16 Q17 Q18 Q19 Q20