Given $z = 1 - 2i$, and $z + a\bar{z} + b = 0$, where $a, b$ are real numbers, then A. $a = 1, b = -2$ B. $a = -1, b = 2$ C. $a = 1, b = 2$ D. $a = -1, b = -2$
Given $z = 1 - 2i$, and $z + a\bar{z} + b = 0$, where $a, b$ are real numbers, then\\
A. $a = 1, b = -2$\\
B. $a = -1, b = 2$\\
C. $a = 1, b = 2$\\
D. $a = -1, b = -2$