Let $z \in \mathbb{C}$. We denote $C_z$ (respectively $\Omega_z$) the set of points in the plane with complex affixe $Z$ such that $|Z(Z-2z)| = 1$ (respectively $|Z(Z-2z)| < 1$). In this question we assume that $z$ is a real number denoted $a$. We work in the orthonormal frame $\mathcal{R}'$ with center $O'$ with affixe $a$, obtained from $\mathcal{R}$ by translation. Show that an equation of the curve $C_a$ in ``polar coordinates $(\rho, \theta)$'' in the frame $\mathcal{R}'$ is $$\left(\rho^2 + a^2\right)^2 - 4a^2 \rho^2 \cos^2\theta = 1$$
Let $z \in \mathbb{C}$. We denote $C_z$ (respectively $\Omega_z$) the set of points in the plane with complex affixe $Z$ such that $|Z(Z-2z)| = 1$ (respectively $|Z(Z-2z)| < 1$).\\
In this question we assume that $z$ is a real number denoted $a$. We work in the orthonormal frame $\mathcal{R}'$ with center $O'$ with affixe $a$, obtained from $\mathcal{R}$ by translation.\\
Show that an equation of the curve $C_a$ in ``polar coordinates $(\rho, \theta)$'' in the frame $\mathcal{R}'$ is
$$\left(\rho^2 + a^2\right)^2 - 4a^2 \rho^2 \cos^2\theta = 1$$