We call the commutant of $f$ the set $\mathcal{C}(f) = \{g \in \mathcal{L}(E) \mid f \circ g = g \circ f\}$. Show that $\mathcal{C}(f)$ is a subalgebra of $\mathcal{L}(E)$.
We call the commutant of $f$ the set $\mathcal{C}(f) = \{g \in \mathcal{L}(E) \mid f \circ g = g \circ f\}$. Show that $\mathcal{C}(f)$ is a subalgebra of $\mathcal{L}(E)$.