The real number $x$ satisfies $$\frac{|x|^2 - |x| - 2}{2|x| - |x|^2 - 2} > 2$$ if and only if $x$ belongs to\\ (A) $(-2, -1) \cup (1, 2)$\\ (B) $(-2/3, 0) \cup (0, 2/3)$\\ (C) $(-1, -2/3) \cup (2/3, 1)$\\ (D) $(-1, 0) \cup (0, 1)$