If the distance of the point $\mathrm { P } ( 1 , - 2,1 )$ from the plane $\mathrm { x } + 2 \mathrm { y } - 2 z = \alpha$, where $\alpha > 0$, is 5 , then the foot of the perpendicular from $P$ to the plane is\\
A) $\left( \frac { 8 } { 3 } , \frac { 4 } { 3 } , - \frac { 7 } { 3 } \right)$\\
B) $\left( \frac { 4 } { 3 } , - \frac { 4 } { 3 } , \frac { 1 } { 3 } \right)$\\
C) $\left( \frac { 1 } { 3 } , \frac { 2 } { 3 } , \frac { 10 } { 3 } \right)$\\
D) $\left( \frac { 2 } { 3 } , - \frac { 1 } { 3 } , \frac { 5 } { 2 } \right)$