jee-main 2020 Q62

jee-main · India · session2_02sep_shift1 Composite & Inverse Functions Determine Domain or Range of a Composite Function

The domain of the function $f(x) = \sin^{-1}\left(\frac{|x| + 5}{x^{2} + 1}\right)$ is $(-\infty, -a] \cup [a, \infty)$, then $a$ is equal to
(1) $\frac{\sqrt{17}}{2}$
(2) $\frac{\sqrt{17} - 1}{2}$
(3) $\frac{1 + \sqrt{17}}{2}$
(4) $\frac{\sqrt{17}}{2} + 1$

The domain of the function $f(x) = \sin^{-1}\left(\frac{|x| + 5}{x^{2} + 1}\right)$ is $(-\infty, -a] \cup [a, \infty)$, then $a$ is equal to\\
(1) $\frac{\sqrt{17}}{2}$\\
(2) $\frac{\sqrt{17} - 1}{2}$\\
(3) $\frac{1 + \sqrt{17}}{2}$\\
(4) $\frac{\sqrt{17}}{2} + 1$

Paper Questions

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