jee-main 2020 Q69

jee-main · India · session2_04sep_shift2 Vectors: Lines & Planes Distance Computation (Point-to-Plane or Line-to-Line)
The distance of the point $( 1 , - 2,3 )$ from the plane $x - y + z = 5$ measured parallel to the line $\frac { x } { 2 } = \frac { y } { 3 } = \frac { z } { - 6 }$ is:
(1) $\frac { 7 } { 5 }$
(2) 1
(3) $\frac { 1 } { 7 }$
(4) 7
The distance of the point $( 1 , - 2,3 )$ from the plane $x - y + z = 5$ measured parallel to the line $\frac { x } { 2 } = \frac { y } { 3 } = \frac { z } { - 6 }$ is:\\
(1) $\frac { 7 } { 5 }$\\
(2) 1\\
(3) $\frac { 1 } { 7 }$\\
(4) 7