Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated ?\\
(1) $2 ! 3 ! 4$ !\\
(2) $( 3 ! ) ^ { 3 } \cdot ( 4 ! )$\\
(3) $( 3 ! ) 2 . ( 4 ! )$\\
(4) $3 ! ( 4 ! ) ^ { 3 }$