jee-main 2021 Q70

jee-main · India · session2_18mar_shift2 Sine and Cosine Rules Heights and distances / angle of elevation problem
A pole stands vertically inside a triangular park $ABC$. Let the angle of elevation of the top of the pole from each corner of the park be $\frac { \pi } { 3 }$. If the radius of the circumcircle of $\triangle ABC$ is 2 , then the height of the pole is equal to:
(1) $\frac { 2 \sqrt { 3 } } { 3 }$
(2) $2 \sqrt { 3 }$
(3) $\sqrt { 3 }$
(4) $\frac { 1 } { \sqrt { 3 } }$
A pole stands vertically inside a triangular park $ABC$. Let the angle of elevation of the top of the pole from each corner of the park be $\frac { \pi } { 3 }$. If the radius of the circumcircle of $\triangle ABC$ is 2 , then the height of the pole is equal to:\\
(1) $\frac { 2 \sqrt { 3 } } { 3 }$\\
(2) $2 \sqrt { 3 }$\\
(3) $\sqrt { 3 }$\\
(4) $\frac { 1 } { \sqrt { 3 } }$