Let $a$ be a real number such that the function $f ( x ) = a x ^ { 2 } + 6 x - 15 , x \in R$ is increasing in $( - \infty , \frac { 3 } { 4 } )$ and decreasing in $\left( \frac { 3 } { 4 } , \infty \right)$. Then the function $g ( x ) = a x ^ { 2 } - 6 x + 15 , x \in R$ has a\\
(1) local maximum at $x = - \frac { 3 } { 4 }$\\
(2) local minimum at $x = - \frac { 3 } { 4 }$\\
(3) local maximum at $x = \frac { 3 } { 4 }$\\
(4) local minimum at $x = \frac { 3 } { 4 }$