If the tangents drawn at the point $O(0,0)$ and $P(1+\sqrt{5}, 2)$ on the circle $x^2 + y^2 - 2x - 4y = 0$ intersect at the point $Q$, then the area of the triangle $OPQ$ is equal to\\
(1) $\frac{3+\sqrt{5}}{2}$\\
(2) $\frac{4+2\sqrt{5}}{2}$\\
(3) $\frac{5+3\sqrt{5}}{2}$\\
(4) $\frac{7+3\sqrt{5}}{2}$