ap-calculus-ab 2007 Q3

ap-calculus-ab · Usa · free-response Chain Rule Chain Rule with Table-Defined Functions
The functions $f$ and $g$ are differentiable for all real numbers, and $g$ is strictly increasing. The table below gives values of the functions and their first derivatives at selected values of $x$.
$x$$f(x)$$f^{\prime}(x)$$g(x)$$g^{\prime}(x)$
16425
29231
310-442
4-1367

The function $h$ is given by $h(x) = f(g(x)) - 6$.
(a) Explain why there must be a value $r$ for $1 < r < 3$ such that $h(r) = -5$.
(b) Explain why there must be a value $c$ for $1 < c < 3$ such that $h^{\prime}(c) = -5$.
(c) Let $w$ be the function given by $w(x) = \int_{1}^{g(x)} f(t)\, dt$. Find the value of $w^{\prime}(3)$.
(d) If $g^{-1}$ is the inverse function of $g$, write an equation for the line tangent to the graph of $y = g^{-1}(x)$ at $x = 2$.
The functions $f$ and $g$ are differentiable for all real numbers, and $g$ is strictly increasing. The table below gives values of the functions and their first derivatives at selected values of $x$.
\begin{center}
\begin{tabular}{ | c | | c | c | c | c | }
\hline
$x$ & $f(x)$ & $f^{\prime}(x)$ & $g(x)$ & $g^{\prime}(x)$ \\
\hline
1 & 6 & 4 & 2 & 5 \\
\hline
2 & 9 & 2 & 3 & 1 \\
\hline
3 & 10 & -4 & 4 & 2 \\
\hline
4 & -1 & 3 & 6 & 7 \\
\hline
\end{tabular}
\end{center}
The function $h$ is given by $h(x) = f(g(x)) - 6$.\\
(a) Explain why there must be a value $r$ for $1 < r < 3$ such that $h(r) = -5$.\\
(b) Explain why there must be a value $c$ for $1 < c < 3$ such that $h^{\prime}(c) = -5$.\\
(c) Let $w$ be the function given by $w(x) = \int_{1}^{g(x)} f(t)\, dt$. Find the value of $w^{\prime}(3)$.\\
(d) If $g^{-1}$ is the inverse function of $g$, write an equation for the line tangent to the graph of $y = g^{-1}(x)$ at $x = 2$.