Let the system of linear equations\\
$- x + 2 y - 9 z = 7$\\
$- x + 3 y + 7 z = 9$\\
$- 2 x + y + 5 z = 8$\\
$- 3 x + y + 13 z = \lambda$\\
has a unique solution $x = \alpha , y = \beta , z = \gamma$. Then the distance of the point $( \alpha , \beta , \gamma )$ from the plane $2 x - 2 y + z = \lambda$ is\\
(1) 11\\
(2) 7\\
(3) 9\\
(4) 13