jee-main 2024 Q5

jee-main · India · session1_29jan_shift2 Work done and energy Conservation of energy on frictionless tracks and pendulums

A bob of mass $m$ is suspended by a light string of length $L$. It is imparted a minimum horizontal velocity at the lowest point $A$ such that it just completes half circle reaching the top most position $B$. The ratio of kinetic energies $\frac { ( \text { K.E. } ) _ { A } } { ( \text { K.E. } ) _ { B } }$ is:
(1) $3 : 2$
(2) $5 : 1$
(3) $2 : 5$
(4) $1 : 5$

A bob of mass $m$ is suspended by a light string of length $L$. It is imparted a minimum horizontal velocity at the lowest point $A$ such that it just completes half circle reaching the top most position $B$. The ratio of kinetic energies $\frac { ( \text { K.E. } ) _ { A } } { ( \text { K.E. } ) _ { B } }$ is:\\
(1) $3 : 2$\\
(2) $5 : 1$\\
(3) $2 : 5$\\
(4) $1 : 5$

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