If the system of linear equations
$$\begin{aligned}
& x - 2 y + z = - 4 \\
& 2 x + \alpha y + 3 z = 5 \\
& 3 x - y + \beta z = 3
\end{aligned}$$
has infinitely many solutions, then $12 \alpha + 13 \beta$ is equal to\\
(1) 60\\
(2) 64\\
(3) 54\\
(4) 58