This exercise is a multiple choice questionnaire. For each of the following questions, only one of the four proposed answers is correct. A correct answer earns one point. An incorrect answer, multiple answers, or no answer to a question earns or loses no points.

In space with respect to an orthonormal coordinate system $(O; \vec{\imath}, \vec{\jmath}, \vec{k})$, we consider the points $A(1; 0; 2)$, $B(2; 1; 0)$, $C(0; 1; 2)$ and the line $\Delta$ whose parametric representation is:
$$\left\{\begin{array}{rl}x & = 1 + 2t \\ y & = -2 + t \\ z & = 4 - t\end{array}, t \in \mathbb{R}\right.$$

\begin{enumerate}
  \item Which of the following points belongs to the line $\Delta$?

Answer A: $M(2; 1; -1)$;\\
Answer B: $N(-3; -4; 6)$;\\
Answer C: $P(-3; -4; 2)$;\\
Answer D: $Q(-5; -5; 1)$.

  \item The vector $\overrightarrow{AB}$ has coordinates:

$$\begin{array}{ll}
\text{Answer A}: \left(\begin{array}{c} 1.5 \\ 0.5 \\ 1 \end{array}\right); & \text{Answer B}: \left(\begin{array}{c} -1 \\ -1 \\ 2 \end{array}\right); \\
\text{Answer C}: \left(\begin{array}{c} 1 \\ 1 \\ -2 \end{array}\right) & \text{Answer D}: \left(\begin{array}{l} 3 \\ 1 \\ 2 \end{array}\right).
\end{array}$$

  \item A parametric representation of the line (AB) is:

$$\begin{array}{ll}
\text{Answer A}: \left\{\begin{array}{l} x = 1 + 2t \\ y = t \\ z = 2 \end{array}, t \in \mathbb{R}\right. & \text{Answer B}: \left\{\begin{array}{l} x = 2 - t \\ y = 1 - t \\ z = 2t \end{array}, t \in \mathbb{R}\right. \\
\text{Answer C}: \left\{\begin{array}{l} x = 2 + t \\ y = 1 + t \\ z = 2t \end{array}, t \in \mathbb{R}\right. & \text{Answer D}: \left\{\begin{array}{l} x = 1 + t \\ y = 1 + t \\ z = 2 - 2t \end{array}, t \in \mathbb{R}\right.
\end{array}$$

  \item A Cartesian equation of the plane passing through point C and orthogonal to the line $\Delta$ is:\\
Answer A: $x - 2y + 4z - 6 = 0$;\\
Answer B: $2x + y - z + 1 = 0$;\\
Answer C: $2x + y - z - 1 = 0$;\\
Answer D: $y + 2z - 5 = 0$.

  \item We consider the point D defined by the vector relation $\overrightarrow{OD} = 3\overrightarrow{OA} - \overrightarrow{OB} - \overrightarrow{OC}$.

Answer A: $\overrightarrow{AD}$, $\overrightarrow{AB}$, $\overrightarrow{AC}$ are coplanar;\\
Answer B: $\overrightarrow{AD} = \overrightarrow{BC}$;\\
Answer C: D has coordinates $(3; -1; -1)$;\\
Answer D: the points A, B, C and D are collinear.
\end{enumerate}