In a bag there are a total of nine balls: one white, three red and five black. The white ball is worth five points, a red ball is worth three points, and a black ball is worth one point. Two balls are taken from the bag together, and the trial is scored by the sum of the values of the two balls. (1) The highest possible score is $\mathbf{A}$, and the probability that it happens is $\dfrac{\mathbf{B}}{\mathbf{CD}}$. (2) The probability that the score is 6 is $\dfrac{\mathbf{E}}{\mathbf{F}}$. (3) The expected value of the score is $\dfrac{\mathbf{GH}}{\mathbf{I}}$.
In a bag there are a total of nine balls: one white, three red and five black. The white ball is worth five points, a red ball is worth three points, and a black ball is worth one point. Two balls are taken from the bag together, and the trial is scored by the sum of the values of the two balls.
(1) The highest possible score is $\mathbf{A}$, and the probability that it happens is $\dfrac{\mathbf{B}}{\mathbf{CD}}$.
(2) The probability that the score is 6 is $\dfrac{\mathbf{E}}{\mathbf{F}}$.
(3) The expected value of the score is $\dfrac{\mathbf{GH}}{\mathbf{I}}$.