kyotsu-test 2014 QCourse2-IV-Q2

kyotsu-test · Japan · eju-math__session2 Reduction Formulae Evaluate a Closed-Form Expression Using the Reduction Formula
Given the function in $x$
$$f _ { n } ( x ) = \sin ^ { n } x \quad ( n = 1,2,3 , \cdots ) ,$$
answer the following questions.
(1) Consider the cases in which the equality
$$\lim _ { x \rightarrow 0 } \frac { a - x ^ { 2 } - \left( b - x ^ { 2 } \right) ^ { 2 } } { f _ { n } ( x ) } = c$$
holds for three real numbers $a , b$ and $c$.
(i) We have $a = b$.
(ii) When $n = 2$, if $c = 6$, then $b = \frac { \mathbf { P } } { \mathbf { Q } }$.
(iii) When $n = 4$, then $b = \frac { \mathbf { R } } { \mathbf { S } }$ and $c = - \mathbf { T }$.
(2) For this $f _ { n } ( x )$, consider the definite integral
$$I _ { n } = \int _ { 0 } ^ { \frac { \pi } { 2 } } f _ { n } ( x ) \sin 2 x \, d x \quad ( n = 1,2,3 , \cdots )$$
When the integral is calculated, we have
$$I _ { n } = \frac { \mathbf { U } } { n + \mathbf { V } } .$$
Hence we obtain
$$\lim _ { n \rightarrow \infty } \left( I _ { n - 1 } + I _ { n } + I _ { n + 1 } + \cdots + I _ { 2 n - 2 } \right) = \int _ { 0 } ^ { \mathbf { W } } \frac { \mathbf { X } } { \mathbf { Y } + x } \, dx = \log \mathbf { Z }$$
Given the function in $x$

$$f _ { n } ( x ) = \sin ^ { n } x \quad ( n = 1,2,3 , \cdots ) ,$$

answer the following questions.\\
(1) Consider the cases in which the equality

$$\lim _ { x \rightarrow 0 } \frac { a - x ^ { 2 } - \left( b - x ^ { 2 } \right) ^ { 2 } } { f _ { n } ( x ) } = c$$

holds for three real numbers $a , b$ and $c$.\\
(i) We have $a = b$.\\
(ii) When $n = 2$, if $c = 6$, then $b = \frac { \mathbf { P } } { \mathbf { Q } }$.\\
(iii) When $n = 4$, then $b = \frac { \mathbf { R } } { \mathbf { S } }$ and $c = - \mathbf { T }$.\\
(2) For this $f _ { n } ( x )$, consider the definite integral

$$I _ { n } = \int _ { 0 } ^ { \frac { \pi } { 2 } } f _ { n } ( x ) \sin 2 x \, d x \quad ( n = 1,2,3 , \cdots )$$

When the integral is calculated, we have

$$I _ { n } = \frac { \mathbf { U } } { n + \mathbf { V } } .$$

Hence we obtain

$$\lim _ { n \rightarrow \infty } \left( I _ { n - 1 } + I _ { n } + I _ { n + 1 } + \cdots + I _ { 2 n - 2 } \right) = \int _ { 0 } ^ { \mathbf { W } } \frac { \mathbf { X } } { \mathbf { Y } + x } \, dx = \log \mathbf { Z }$$