If the possible values of random variable $X$ are $1 , 2 , 3 , 4$ , and the probability $P ( X = k )$ is proportional to $\frac { 1 } { k }$ , then the probability $P ( X = 3 )$ is $\frac { \text{(9)(11)} } { \text{(10)(11)} }$ . (Reduce to lowest terms)
If the possible values of random variable $X$ are $1 , 2 , 3 , 4$ , and the probability $P ( X = k )$ is proportional to $\frac { 1 } { k }$ , then the probability $P ( X = 3 )$ is $\frac { \text{(9)(11)} } { \text{(10)(11)} }$ . (Reduce to lowest terms)