If $x, y$ are two positive real numbers satisfying $x^{-\frac{1}{3}} y^{2} = 1$ and $2\log y = 1$, then $\frac{x - y^{2}}{10} =$ (13--1) (13--2).
If $x, y$ are two positive real numbers satisfying $x^{-\frac{1}{3}} y^{2} = 1$ and $2\log y = 1$, then $\frac{x - y^{2}}{10} =$ (13--1) (13--2).