Let $a$ and $b$ be real numbers (where $a > 0$). If the polynomial $ax^{2} + (2a+b)x - 12$ divided by $x^{2} + (2-a)x - 2a$ gives a remainder of 6, then the ordered pair $(a, b) = $ (14--1), 14--2).
Let $a$ and $b$ be real numbers (where $a > 0$). If the polynomial $ax^{2} + (2a+b)x - 12$ divided by $x^{2} + (2-a)x - 2a$ gives a remainder of 6, then the ordered pair $(a, b) = $ (14--1), 14--2).