Direct Conditional Probability Computation from Definitions
The question gives probability values (e.g., P(A∩B), P(A), P(B|A)) and asks to compute a conditional probability or related quantity directly from the definition P(B|A) = P(A∩B)/P(A) without a real-world narrative.
Let $A$ and $E$ be any two events with positive probabilities Statement I: $P ( E / A ) \geq P ( A / E ) P ( E )$. Statement II: $P ( A / E ) \geq P ( A \cap E )$. (1) Both the statements are false (2) Both the statements are true (3) Statement-I is false, Statement-II is true (4) Statement - I is true, Statement - II is false
Let $A$ and $B$ be two non-null events such that $A \subset B$. Then, which of the following statements is always correct? (1) $P(A \mid B) \geq P(A)$ (2) $P(A \mid B) = P(B) - P(A)$ (3) $P(A \mid B) \leq P(A)$ (4) $P(A \mid B) = 1$
Let $A$ and $B$ be two events such that $P ( B \mid A ) = \frac { 2 } { 5 } , P ( A \mid B ) = \frac { 1 } { 7 }$ and $P ( A \cap B ) = \frac { 1 } { 9 }$. Consider $( S1 )\; P \left( A ^ { \prime } \cup B \right) = \frac { 5 } { 6 }$, $( S2 )\; P \left( A ^ { \prime } \cap B ^ { \prime } \right) = \frac { 1 } { 18 }$. Then (1) Both $(S1)$ and $(S2)$ are true (2) Both $(S1)$ and $(S2)$ are false (3) Only $(S1)$ is true (4) Only $(S2)$ is true
Let Ajay will not appear in JEE exam with probability $p = \frac{2}{7}$, while both Ajay and Vijay will appear in the exam with probability $q = \frac{1}{5}$. Then the probability, that Ajay will appear in the exam and Vijay will not appear is: (1) $\frac{9}{35}$ (2) $\frac{18}{35}$ (3) $\frac{24}{35}$ (4) $\frac{3}{35}$
If $A$ and $B$ are two events such that $P ( A \cap B ) = 0.1$, and $P ( A \mid B )$ and $P ( B \mid A )$ are the roots of the equation $12 x ^ { 2 } - 7 x + 1 = 0$, then the value of $\frac { \mathrm { P } ( \overline { \mathrm { A } } \cup \overline { \mathrm { B } } ) } { \mathrm { P } ( \overline { \mathrm { A } } \cap \overline { \mathrm { B } } ) }$ is : (1) $\frac { 4 } { 3 }$ (2) $\frac { 7 } { 4 }$ (3) $\frac { 5 } { 3 }$ (4) $\frac { 9 } { 4 }$
Knowing that $P ( A ) = 0.5 , P ( A / B ) = 0.625$ and $P ( A \cup B ) = 0.65$, find:\ a) ( 1.5 points) $P ( B )$ and $P ( A \cap B )$.\ b) (1 point) $P ( A / A \cup B )$ and $P ( A \cap B / A \cup B )$
9. Consider the statement about Fred: (}) Every day next week, Fred will do at least one maths problem. If statement (*) is not true, which of the following is certainly true? A Every day next week, Fred will do more than one maths problem. B Some day next week, Fred will do more than one maths problem. C On no day next week will Fred do more than one maths problem. D Every day next week, Fred will do no maths problems. E Some day next week, Fred will do no maths problems. F On no day next week will Fred do no maths problems.
On a table, there are three marbles in total: one red, one blue, and one yellow. These marbles are placed in bags A, B, and C with one marble in each bag, and p: ``There is no red marble in bag A.'' q: ``There is a blue marble in bag B.'' r: ``There is no yellow marble in bag C.'' propositions are given. $$p \wedge ( q \vee r ) ^ { \prime \prime }$$ Given that the proposition is true; what are the colors of the marbles in bags A, B and C respectively? A) Red - Blue - Yellow B) Blue - Red - Yellow C) Blue - Yellow - Red D) Yellow - Red - Blue E) Yellow - Blue - Red
Regarding the subsets $A, B$ and $C$ of the set of natural numbers, the propositions $$\begin{aligned}
& p : 9 \in A \cup B \\
& q : 9 \in A \cap C \\
& r : 9 \notin C
\end{aligned}$$ are given. Given that the proposition $(p \Rightarrow q)' \wedge r'$ is true, which of the following statements are true? I. $9 \in A$ II. $9 \in B$ III. $9 \in C$ A) Only I B) Only III C) I and II D) II and III E) I, II and III