Let z be a complex number satisfying the equality $$i \cdot z + 1 = 2 ( 1 - \bar { z } )$$ What is the real part of the complex number z? A) $\frac { 1 } { 6 }$ B) $\frac { 1 } { 4 }$ C) $\frac { 1 } { 2 }$ D) $\frac { 2 } { 3 }$ E) $\frac { 5 } { 6 }$
$4 z - 3 \bar { z } = \frac { 1 - 18 i } { 2 - i }$\ Which of the following is the complex number $z$ that satisfies this equality?\ A) $- 2 + i$\ B) $- 3 + i$\ C) $4 + 2 i$\ D) $3 - 2 i$\ E) $4 - i$
Let $\bar{z}$ be the conjugate of the complex number $z$, $$\frac { 6 + 2 i } { z } = \bar { z } + i$$ the sum of the complex numbers $z$ that satisfy the equality is what? A) $1 + 3 i$ B) $2 + i$ C) $3 + 2 i$ D) $4 + i$