Substitution to Evaluate Limit of an Integral Expression
The question requires substitution to evaluate an integral that depends on a parameter, then taking a limit of the resulting expression as the parameter tends to a value.
Let $f \in \mathcal { C } ^ { 0 } ( [ a , b ] )$ such that $f ( a ) \neq 0$ and $\varphi \in \mathcal { C } ^ { 1 } ( [ a , b ] )$. For every parameter $t \in \mathbb { R }$, we denote $$F ( t ) = \int _ { a } ^ { b } e ^ { - t \varphi ( x ) } f ( x ) d x$$ Case where the phase $\varphi$ has no critical point in $[ a , b ]$. We assume that $\varphi ^ { \prime } ( x ) > 0$ for all $x \in [ a , b ]$. (a) Show that $\Phi : x \mapsto \varphi ( x ) - \varphi ( a )$ is a bijection from $[ a , b ]$ onto an interval of the form $[ 0 , \beta ]$, and that it is of class $\mathcal { C } ^ { 1 }$. (b) Show that $$F ( t ) \underset { t \rightarrow + \infty } { \sim } \frac { e ^ { - t \varphi ( a ) } f ( a ) } { \varphi ^ { \prime } ( a ) t }$$ Hint. One can reduce to the case treated in question 1a) using a change of variable.
Let $f \in \mathcal { C } ^ { 0 } ( [ a , b ] )$ such that $f ( a ) \neq 0$ and $\varphi \in \mathcal { C } ^ { 1 } ( [ a , b ] )$. For every parameter $t \in \mathbb { R }$, we denote $$F ( t ) = \int _ { a } ^ { b } e ^ { - t \varphi ( x ) } f ( x ) d x$$ Case where the phase $\varphi$ has a critical point at $a$. We now assume that $\varphi \in \mathcal { C } ^ { 2 } ( [ a , b ] )$, $\varphi ^ { \prime } ( a ) = 0 , \varphi ^ { \prime \prime } ( a ) > 0$, and $\varphi ^ { \prime } ( x ) > 0$ for all $\left. \left. x \in \right] a , b \right]$. (a) Show that the formula $\psi ( x ) = \sqrt { \varphi ( x ) - \varphi ( a ) }$ defines a function of class $\mathcal { C } ^ { 1 }$ on $[ a , b ]$. Calculate $\psi ^ { \prime } ( a )$. (b) Show that $\psi$ is a bijection from $[ a , b ]$ onto an interval of the form $[ 0 , \beta ]$. (c) Show that $$F ( t ) \underset { t \rightarrow + \infty } { \sim } \sqrt { \frac { \pi } { 2 \varphi ^ { \prime \prime } ( a ) } } \frac { e ^ { - t \varphi ( a ) } f ( a ) } { \sqrt { t } } .$$ Hint. One can reduce to the case treated in question 1b) using a change of variable.
Let $a < b$ be two real numbers and $f : [a,b] \rightarrow \mathbb{R}$ be an infinitely differentiable function. Let us call (H) the following hypothesis: there exists a unique point $x_0 \in [a,b]$ where $f$ attains its maximum, we have $a < x_0 < b$, and $f''(x_0) \neq 0$. Under hypothesis (H), show that for all $\delta > 0$ such that $\delta < \min(x_0 - a, b - x_0)$, we have the asymptotic equivalence, as $t \rightarrow +\infty$, $$\int_a^b e^{tf(x)} \mathrm{d}x \sim \int_{x_0 - \delta}^{x_0 + \delta} e^{tf(x)} \mathrm{d}x.$$
Let $a < b$ be two real numbers and $f : [ a , b ] \rightarrow \mathbb { R }$ be an infinitely differentiable function. Let us call (H) the following hypothesis: there exists a unique point $x _ { 0 } \in [ a , b ]$ where $f$ attains its maximum, we have $a < x _ { 0 } < b$, and $f ^ { \prime \prime } \left( x _ { 0 } \right) \neq 0$. Under hypothesis $( \mathrm { H } )$, show that for all $\delta > 0$ such that $\delta < \min \left( x _ { 0 } - a , b - x _ { 0 } \right)$, we have the asymptotic equivalence, as $t \rightarrow + \infty$, $$\int _ { a } ^ { b } e ^ { t f ( x ) } \mathrm { d } x \sim \int _ { x _ { 0 } - \delta } ^ { x _ { 0 } + \delta } e ^ { t f ( x ) } \mathrm { d } x$$
1 (1) For a positive integer $k$, let $A_k = \displaystyle\int_{\sqrt{k\pi}}^{\sqrt{(k+1)\pi}} |\sin(x^2)|\,dx$. Prove that the following inequality holds: $$\frac{1}{\sqrt{(k+1)\pi}} \leqq A_k \leqq \frac{1}{\sqrt{k\pi}}$$ (2) For a positive integer $n$, let $B_n = \dfrac{1}{\sqrt{n}}\displaystyle\int_{\sqrt{n\pi}}^{\sqrt{2n\pi}} |\sin(x^2)|\,dx$. Find the limit $\displaystyle\lim_{n\to\infty} B_n$. %% Page 2