Piecewise/Periodic Function Integration

Compute a definite integral of a piecewise-defined or periodic function, requiring splitting the domain, using periodicity, or handling different cases across subintervals.

jee-advanced 2000 Q20 View
20. If $f ( x ) = \left\{ \begin{array} { c c } e ^ { \cos x } \sin x & \text { for } | x | \leq 2 , \\ 2 & \text { otherwise, } \end{array} \right.$ then $\int _ { - 2 } ^ { 3 } f ( x ) d x =$
(A) 0
(B) 1
(C) 2
(D) 3
jee-advanced 2000 Q35 View
35. The value of the integral $\int \mathrm { e } - 1 \mathrm { e } 2 | \log \mathrm { x } / \mathrm { x } | \mathrm { dx }$ is :
(A) $3 / 2$
(B) $5 / 2$
(C) 3
(D) 5
jee-advanced 2010 Q52 View
For any real number x, let $[ \mathrm { x } ]$ denote the largest integer less than or equal to x. Let $f$ be a real valued function defined on the interval $[ - 10,10 ]$ by $$f ( x ) = \left\{ \begin{array} { c c } x - [ x ] & \text { if } [ x ] \text { is odd } \\ 1 + [ x ] - x & \text { if } [ x ] \text { is even } \end{array} \right.$$ Then the value of $\frac { \pi ^ { 2 } } { 10 } \int _ { - 10 } ^ { 10 } f ( x ) \cos \pi x \, d x$ is
jee-advanced 2015 Q46 View
Let $f : \mathbb { R } \rightarrow \mathbb { R }$ be a function defined by $f ( x ) = \left\{ \begin{array} { l l } { [ x ] , } & x \leq 2 \\ 0 , & x > 2 \end{array} \right.$, where $[ x ]$ is the greatest integer less than or equal to $x$. If $I = \int _ { - 1 } ^ { 2 } \frac { x f \left( x ^ { 2 } \right) } { 2 + f ( x + 1 ) } d x$, then the value of $( 4 I - 1 )$ is
jee-advanced 2021 Q11 4 marks View
For any real number $x$, let $\lfloor x \rfloor$ denote the largest integer less than or equal to $x$. If $$I = \int_0^{10} \left\lfloor \frac{10x}{x+1} \right\rfloor dx,$$ then the value of $9I$ is ____.
jee-advanced 2021 Q19 View
For any real number $x$, let $[ x ]$ denote the largest integer less than or equal to $x$. If $$I = \int _ { 0 } ^ { 10 } \left[ \sqrt { \frac { 10 x } { x + 1 } } \right] d x$$ then the value of $9 I$ is $\_\_\_\_$.
jee-main 2012 Q73 View
If the integral $\displaystyle\int_{0}^{10} \frac{\lfloor x \rfloor e^{x}}{e^{\lfloor x \rfloor}} dx = \alpha(e-1)$, then $\alpha$ is equal to (where $\lfloor x \rfloor$ denotes the greatest integer function)
(1) $\frac{1}{e-1}$
(2) $\frac{10}{e-1}$
(3) $\frac{e}{e-1}$
(4) $\frac{e^{10}-1}{e-1}$
jee-main 2020 Q65 View
$\int _ { - \pi } ^ { \pi } | \pi - | \mathrm { x } | | \mathrm { d } x$ is equal to
(1) $\sqrt { 2 } \pi ^ { 2 }$
(2) $2 \pi ^ { 2 }$
(3) $\pi ^ { 2 }$
(4) $\frac { \pi ^ { 2 } } { 2 }$
jee-main 2021 Q73 View
Consider the integral $I = \int _ { 0 } ^ { 10 } \frac { [ x ] e ^ { [ x ] } } { e ^ { x - 1 } } d x$ where $[ x ]$ denotes the greatest integer less than or equal to $x$. Then the value of $I$ is equal to :
(1) $9 ( e - 1 )$
(2) $45 ( e + 1 )$
(3) $45 ( e - 1 )$
(4) $9 ( e + 1 )$
jee-main 2021 Q75 View
Let $a$ be a positive real number such that $\int _ { 0 } ^ { a } e ^ { x - [ x ] } d x = 10 e - 9$ where, $[ x ]$ is the greatest integer less than or equal to $x$. Then, $a$ is equal to:
(1) $10 - \log _ { e } ( 1 + e )$
(2) $10 + \log _ { e } 2$
(3) $10 + \log _ { e } ( 1 + e )$
(4) $10 - \log _ { e } 2$
jee-main 2021 Q75 View
The value of $\int _ { - 1 } ^ { 1 } x ^ { 2 } e ^ { \left[ x ^ { 3 } \right] } d x$, where $[ t ]$ denotes the greatest integer $\leq t$, is :
(1) $\frac { e + 1 } { 3 }$
(2) $\frac { e - 1 } { 3 e }$
(3) $\frac { 1 } { 3 e }$
(4) $\frac { e + 1 } { 3 e }$
jee-main 2021 Q87 View
The value of $\int _ { - 2 } ^ { 2 } \left| 3 x ^ { 2 } - 3 x - 6 \right| d x$ is $\underline{\hspace{1cm}}$.
jee-main 2021 Q75 View
If the integral $\int _ { 0 } ^ { 10 } \frac { [ \sin 2 \pi x ] } { \mathrm { e } ^ { x - [ x ] } } d x = \alpha e ^ { - 1 } + \beta e ^ { - \frac { 1 } { 2 } } + \gamma$, where $\alpha , \beta , \gamma$ are integers and $[ x ]$ denotes the greatest integer less than or equal to $x$, then the value of $\alpha + \beta + \gamma$ is equal to:
(1) 0
(2) 20
(3) 25
(4) 10
jee-main 2021 Q73 View
If $[ x ]$ denotes the greatest integer less than or equal to $x$, then the value of the integral $\int _ { - \pi / 2 } ^ { \pi / 2 } [ [ x ] - \sin x ] \, d x$ is equal to:
(1) $- \pi$
(2) $\pi$
(3) 0
(4) 1
jee-main 2021 Q87 View
Let $[ t ]$ denote the greatest integer $\leq \mathrm { t }$. Then the value of $8 \cdot \int _ { - \frac { 1 } { 2 } } ^ { 1 } ( [ 2 x ] + | x | ) \mathrm { d } x$ is
jee-main 2022 Q74 View
Let $f : R \rightarrow R$ be a function defined by : $f ( x ) = \left\{ \begin{array} { c c } \max _ { t \leq x } \left\{ t ^ { 3 } - 3 t \right\} ; & x \leq 2 \\ x ^ { 2 } + 2 x - 6 ; & 2 < x < 3 \\ { [ x - 3 ] + 9 ; } & 3 \leq x \leq 5 \\ 2 x + 1 ; & x > 5 \end{array} \right.$ Where $[ t ]$ is the greatest integer less than or equal to $t$. Let $m$ be the number of points where $f$ is not differentiable and $I = \int _ { - 2 } ^ { 2 } f ( x ) d x$. Then the ordered pair ( $m , I$ ) is equal to
(1) $\left( 3 , \frac { 27 } { 4 } \right)$
(2) $\left( 3 , \frac { 23 } { 4 } \right)$
(3) $\left( 4 , \frac { 27 } { 4 } \right)$
(4) $\left( 4 , \frac { 23 } { 4 } \right)$
jee-main 2022 Q75 View
Let $[t]$ denote the greatest integer less than or equal to $t$. Then the value of the integral $\int_{-3}^{101} \left([\sin(\pi x)] + e^{[\cos(2\pi x)]}\right) dx$ is equal to
(1) $\frac{52(1-e)}{e}$
(2) $\frac{52}{e}$
(3) $\frac{52(2+e)}{e}$
(4) $\frac{104}{e}$
jee-main 2022 Q76 View
$\int _ { 0 } ^ { 20 \pi } ( | \sin x | + | \cos x | ) ^ { 2 } \, d x$ is equal to:
(1) $10 \pi + 4$
(2) $10 \pi + 2$
(3) $20 \pi - 2$
(4) $20 \pi + 2$
jee-main 2022 Q74 View
If $[t]$ denotes the greatest integer $\leq t$, then the value of $\int_0^1 \left[2x - \left|3x^2 - 5x + 2\right| + 1\right] dx$ is
(1) $\frac{\sqrt{37} + \sqrt{13} - 4}{6}$
(2) $\frac{\sqrt{37} - \sqrt{13} - 4}{6}$
(3) $\frac{-\sqrt{37} - \sqrt{13} + 4}{6}$
(4) $\frac{-\sqrt{37} + \sqrt{13} + 4}{6}$
jee-main 2022 Q87 View
Let $f ( x ) = \max \{ | x + 1 | , | x + 2 | , \ldots , | x + 5 | \}$. Then $\int _ { - 6 } ^ { 0 } f ( x ) \, dx$ is equal to $\_\_\_\_$.
jee-main 2022 Q75 View
The integral $\int _ { 0 } ^ { 1 } \frac { 1 } { 7 ^ { \left[ \frac { 1 } { x } \right] } } d x$, where $[ \cdot ]$ denotes the greatest integer function, is equal to
(1) $1 - 6 \ln \left( \frac { 6 } { 7 } \right)$
(2) $1 + 6 \ln \left( \frac { 6 } { 7 } \right)$
(3) $1 - 7 \ln \left( \frac { 6 } { 7 } \right)$
(4) $1 + 7 \ln \left( \frac { 6 } { 7 } \right)$
jee-main 2022 Q73 View
For any real number $x$, let $\lfloor x \rfloor$ denote the largest integer less than or equal to $x$. Let $f$ be a real-valued function defined on the interval $[-10,10]$ by $f(x) = \begin{cases} x - \lfloor x \rfloor, & \text{if } \lfloor x \rfloor \text{ is odd} \\ 1 + \lfloor x \rfloor - x, & \text{if } \lfloor x \rfloor \text{ is even} \end{cases}$ Then, the value of $\frac { \pi ^ { 2 } } { 10 } \int _ { - 10 } ^ { 10 } f(x) \cos(\pi x)\, dx$ is
(1) 4
(2) 2
(3) 1
(4) 0
jee-main 2022 Q67 View
Let $f : \mathbb { R } \rightarrow \mathbb { R }$ be a function defined as $f ( x ) = a \sin \left( \frac { \pi [ x ] } { 2 } \right) + [ 2 - x ] , a \in \mathbb { R }$, where $[ t ]$ is the greatest integer less than or equal to $t$. If $\lim _ { x \rightarrow - 1 } f ( x )$ exists, then the value of $\int _ { 0 } ^ { 4 } f ( x ) d x$ is equal to
(1) - 1
(2) - 2
(3) 1
(4) 2
jee-main 2022 Q73 View
Let $f ( x ) = 2 + | x | - | x - 1 | + | x + 1 | , x \in R$. Consider $( S 1 ) : f ^ { \prime } \left( - \frac { 3 } { 2 } \right) + f ^ { \prime } \left( - \frac { 1 } { 2 } \right) + f ^ { \prime } \left( \frac { 1 } { 2 } \right) + f ^ { \prime } \left( \frac { 3 } { 2 } \right) = 2$ $( S 2 ) : \int _ { - 2 } ^ { 2 } f ( x ) d x = 12$ Then,
(1) both ( $S 1$ ) and ( $S 2$ ) are correct
(2) both $( S 1 )$ and $( S 2 )$ are wrong
(3) only ( $S 1$ ) is correct
(4) only ( $S 2$ ) is correct
jee-main 2022 Q74 View
$\int _ { 0 } ^ { 2 } \left( \left| 2 x ^ { 2 } - 3 x \right| + \left[ x - \frac { 1 } { 2 } \right] \right) d x$, where $[ t ]$ is the greatest integer function, is equal to
(1) $\frac { 7 } { 6 }$
(2) $\frac { 19 } { 12 }$
(3) $\frac { 31 } { 12 }$
(4) $\frac { 3 } { 2 }$