LFM Pure and Mechanics

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taiwan-gsat 2020 Q4 8 marks True/False or Multiple-Statement Verification View
In the coordinate plane, let $O$ be the origin, and let $A$ and $B$ be two distinct points different from $O$. Let $C_{1}$, $C_{2}$, $C_{3}$ be three points in the plane satisfying $\overrightarrow{OC}_{n} = \overrightarrow{OA} + n\overrightarrow{OB}$, $n = 1, 2, 3$. Select the correct options.
(1) $\overrightarrow{OC}_{1} \neq \overrightarrow{0}$
(2) $\overline{OC_{1}} < \overline{OC_{2}} < \overline{OC_{3}}$
(3) $\overrightarrow{OC}_{1} \cdot \overrightarrow{OA} < \overrightarrow{OC}_{2} \cdot \overrightarrow{OA} < \overrightarrow{OC}_{3} \cdot \overrightarrow{OA}$
(4) $\overrightarrow{OC_{1}} \cdot \overrightarrow{OB} < \overrightarrow{OC_{2}} \cdot \overrightarrow{OB} < \overrightarrow{OC_{3}} \cdot \overrightarrow{OB}$
(5) $C_{1}$, $C_{2}$, $C_{3}$ are collinear
A biased coin has probability $\frac { 1 } { 3 }$ of showing heads and probability $\frac { 2 } { 3 }$ of showing tails. On a coordinate plane, a game piece moves to the next position based on the result of flipping this coin, according to the following rules: (I) If heads appears, the piece moves from its current position in the direction and distance of vector $( - 1,2 )$ to the next position; (II) If tails appears, the piece moves from its current position in the direction and distance of vector $( 1,0 )$ to the next position. For example: If the game piece is currently at coordinates $( 2,4 )$ and tails appears, the piece moves to coordinates $( 3,4 )$. Suppose the game piece starts at the origin $( 0,0 )$ and, according to the above rules, flips the coin 6 times consecutively, with each flip being independent. After 6 moves, the game piece is most likely to stop at coordinates (12), (13)).
taiwan-gsat 2021 QC 6 marks Expressing a Vector as a Linear Combination View
Consider a trapezoid $ABCD$ where $\overline { AB }$ is parallel to $\overline { DC }$ . It is known that points $E$ and $F$ lie on diagonals $\overline { AC }$ and $\overline { BD }$ respectively, and $\overline { AB } = \frac { 2 } { 5 } \overline { DC }$ , $\overline { AE } = \frac { 3 } { 2 } \overline { EC }$ , $\overline { BF } = \frac { 2 } { 3 } \overline { FD }$ . If vector $\overrightarrow { FE }$ is expressed as $\alpha \overrightarrow { AC } + \beta \overrightarrow { AD }$ , then the real numbers $\alpha = \frac { \text{(16)} } { \text{(17)(18)} } , \beta = \frac { \text{(19)(20)} } { \text{(21)(22)} }$ . (Express as fractions in lowest terms)
taiwan-gsat 2021 QF 5 marks Area Computation Using Vectors View
As shown in the figure, a robot starts from a point $P$ on the ground and moves according to the following rules: First, move forward 1 meter in a certain direction, then rotate counterclockwise $45 ^ { \circ }$ in the direction of movement; move forward 1 meter in the new direction, then rotate clockwise $90 ^ { \circ }$ in the direction of movement; move forward 1 meter in the new direction, then rotate counterclockwise $45 ^ { \circ }$ in the direction of movement; move forward 1 meter in the new direction, then rotate clockwise $90 ^ { \circ }$ in the direction of movement, and so on. The path traced by the robot forms a closed region. The area of this closed region is (28) + (29) $\sqrt { (30) }$ square meters. (Express as a fraction in simplest radical form)
taiwan-gsat 2021 Q4 5 marks Area Computation Using Vectors View
Let $\vec { a }$ and $\vec { b }$ be non-zero vectors in the plane. If the area of the triangle formed by $2 \vec { a } + \vec { b }$ and $\vec { a } + 2 \vec { b }$ is 6, what is the area of the triangle formed by $3 \vec { a } + \vec { b }$ and $\vec { a } + 3 \vec { b }$?
(1) 8
(2) 9
(3) 12
(4) 13.5
(5) 16
taiwan-gsat 2022 Q4 5 marks Simplify or Evaluate a Logarithmic Expression View
On a coordinate plane, it is known that vector $\overrightarrow{PQ} = \left(\log \frac{1}{5}, -10^{-5}\right)$, where point $P$ has coordinates $\left(\log \frac{1}{2}, 2^{-5}\right)$. Select the correct option.
(1) Point $Q$ is in the first quadrant
(2) Point $Q$ is in the second quadrant
(3) Point $Q$ is in the third quadrant
(4) Point $Q$ is in the fourth quadrant
(5) Point $Q$ is on a coordinate axis
taiwan-gsat 2022 Q9 5 marks True/False or Multiple-Statement Verification View
Let $P$ be a point inside $\triangle A B C$, and $\overrightarrow { A P } = a \overrightarrow { A B } + b \overrightarrow { A C }$ , where $a , b$ are distinct real numbers. Let $Q , R$ be on the same plane, with $\overrightarrow { A Q } = b \overrightarrow { A B } + a \overrightarrow { A C } , ~ \overrightarrow { A R } = a \overrightarrow { A B } + ( b - 0.05 ) \overrightarrow { A C }$ . Select the correct options.
(1) $Q , R$ are also both inside $\triangle A B C$
(2) $| \overrightarrow { A P } | = | \overrightarrow { A Q } |$
(3) Area of $\triangle A B P$ = Area of $\triangle A C Q$
(4) Area of $\triangle B C P$ = Area of $\triangle B C Q$
(5) Area of $\triangle A B P$ > Area of $\triangle A B R$
taiwan-gsat 2022 Q11 5 marks Dot Product Computation View
Consider points $O(0,0), A, B, C, D, E, F, G$ on a coordinate plane, where points $B$, $C$ and $D$, $E$ and $F$, $G$ and $A$ are located in the first, second, third, and fourth quadrants respectively. If $\vec{v}$ is a vector on the coordinate plane satisfying $\vec{v} \cdot \overrightarrow{OA} > 0$ and $\vec{v} \cdot \overrightarrow{OB} > 0$, then the dot product of $\vec{v}$ with which of the following vectors must be negative?
(1) $\overrightarrow{OC}$
(2) $\overrightarrow{OD}$
(3) $\overrightarrow{OE}$
(4) $\overrightarrow{OF}$
(5) $\overrightarrow{OG}$
taiwan-gsat 2022 Q14 5 marks Optimization on a Circle View
On a coordinate plane, there is a circle with radius 7 and center $O$. It is known that points $A, B$ are on the circle and $\overline{AB} = 8$. Then the dot product $\overrightarrow{OA} \cdot \overrightarrow{OB} =$ (14--1) (14--2).
taiwan-gsat 2022 Q15 4 marks Function Analysis via Identity Transformation View
Consider vectors $\vec{a}$ and $\vec{b}$ on the coordinate plane satisfying $|\vec{a}| + |\vec{b}| = 9$ and $|\vec{a} - \vec{b}| = 7$. Let $|\vec{a}| = x$, where $1 < x < 8$, and let the angle between $\vec{a}$ and $\vec{b}$ be $\theta$. Using the triangle formed by vectors $\vec{a}$, $\vec{b}$, and $\vec{a} - \vec{b}$, we can express $\cos\theta$ in terms of $x$ as $\frac{c}{9x - x^2} + d$, where $c$ and $d$ are constants with $c > 0$. Let this expression be $f(x)$, with domain $\{x \mid 1 < x < 8\}$. Find $f(x)$ and its derivative. (Non-multiple choice question, 4 points)
Consider vectors $\vec{a}$ and $\vec{b}$ on the coordinate plane satisfying $|\vec{a}| + |\vec{b}| = 9$ and $|\vec{a} - \vec{b}| = 7$. Let $|\vec{a}| = x$, where $1 < x < 8$, and let the angle between $\vec{a}$ and $\vec{b}$ be $\theta$. Using the triangle formed by vectors $\vec{a}$, $\vec{b}$, and $\vec{a} - \vec{b}$, we can express $\cos\theta$ in terms of $x$ as $f(x) = \frac{c}{9x - x^2} + d$, where $c$ and $d$ are constants with $c > 0$, with domain $\{x \mid 1 < x < 8\}$. Explain where $f(x)$ is increasing and decreasing in its domain. Determine the value of $x$ for which the angle $\theta$ between $\vec{a}$ and $\vec{b}$ is maximum. (Non-multiple choice question, 4 points)
Consider vectors $\vec{a}$ and $\vec{b}$ on the coordinate plane satisfying $|\vec{a}| + |\vec{b}| = 9$ and $|\vec{a} - \vec{b}| = 7$. Let $|\vec{a}| = x$, where $1 < x < 8$, and let the angle between $\vec{a}$ and $\vec{b}$ be $\theta$. Using the triangle formed by vectors $\vec{a}$, $\vec{b}$, and $\vec{a} - \vec{b}$, we can express $\cos\theta$ in terms of $x$ as $f(x) = \frac{c}{9x - x^2} + d$, where $c$ and $d$ are constants with $c > 0$, with domain $\{x \mid 1 < x < 8\}$. Using the linear approximation (first-order approximation) of $f(x)$, find the approximate value of $\cos\theta$ when $x = 4.96$. (Non-multiple choice question, 4 points)
taiwan-gsat 2023 Q1 6 marks Vector Word Problem / Physical Application View
On a coordinate plane, a particle starts from point $( - 3 , - 2 )$ and moves 5 units in the direction of vector $( a , 1 )$ and arrives exactly at the $x$-axis, where $a$ is a positive real number. What is the value of $a$?
(1) $\frac { \sqrt { 13 } } { 2 }$
(2) 2
(3) $\sqrt { 5 }$
(4) $\frac { \sqrt { 21 } } { 2 }$
(5) $2 \sqrt { 6 }$
taiwan-gsat 2023 Q6 5 marks Dot Product Computation View
In coordinate space, consider a unit cube with edge length 1, with one vertex $O$ fixed. From the seven vertices other than $O$, two distinct points are randomly selected, denoted as $P$ and $Q$. What is the expected value of the dot product $\overrightarrow{OP} \cdot \overrightarrow{OQ}$ among the following options?
(1) $\frac{4}{7}$
(2) $\frac{5}{7}$
(3) $\frac{6}{7}$
(4) 1
(5) $\frac{8}{7}$
taiwan-gsat 2023 Q9 6 marks Magnitude of Vector Expression View
It is known that a right triangle $\triangle A B C$ has side lengths $\overline { A B } = \sqrt { 7 }$, $\overline { A C } = \sqrt { 3 }$, $\overline { B C } = 2$. If isosceles triangles $\triangle M A B$ and $\triangle N A C$ with vertex angles equal to $120 ^ { \circ }$ are constructed outside $\triangle A B C$ using $\overline { A B }$ and $\overline { A C }$ as bases respectively, then $\overline { M N } ^ { 2 } =$ . (Express as a fraction in lowest terms)
taiwan-gsat 2023 Q15 5 marks Perpendicularity or Parallel Condition View
Let $O$, $A$, $B$ be three non-collinear points on the coordinate plane, where the vector $\overrightarrow{OA}$ is perpendicular to $\overrightarrow{OB}$. If points $C$ and $D$ are on the line $AB$ satisfying $\overrightarrow{OC} = \frac{3}{5}\overrightarrow{OA} + \frac{2}{5}\overrightarrow{OB}$, $3\overline{AD} = 8\overline{BD}$, and $\overrightarrow{OC}$ is perpendicular to $\overrightarrow{OD}$, then $\frac{\overline{OB}}{\overline{OA}} = $ (Express as a fraction in lowest terms)
taiwan-gsat 2023 Q15 5 marks Dot Product Computation View
As shown in the figure, a point $P_{0}$ moves forward 2 units in a certain direction to reach point $P_{1}$, then turns left 15 degrees in the direction of motion; moves forward 2 units in the new direction to reach point $P_{2}$, then turns left 15 degrees again; moves forward 2 units in the new direction to reach point $P_{3}$, and so on.
The dot product of vectors $\overrightarrow{P_{2}P_{3}}$ and $\overrightarrow{P_{5}P_{6}}$ is $\square$. (Express as a simplified radical)
On the coordinate plane, $O$ is the origin, and points $A(1,0)$ and $B(-2,0)$ are given. There are also two points $P$ and $Q$ in the upper half-plane satisfying $\overline{AP} = \overline{OA}$, $\overline{BQ} = \overline{OB}$, $\angle POQ$ is a right angle. Let $\angle AOP = \theta$.
The length of line segment $\overline{OP}$ is which of the following options? (Single choice question, 3 points)
(1) $\sin\theta$
(2) $\cos\theta$
(3) $2\sin\theta$
(4) $2\cos\theta$
(5) $\cos 2\theta$
taiwan-gsat 2023 Q19 6 marks Multi-step composite figure problem View
On the coordinate plane, $O$ is the origin, and points $A(1,0)$ and $B(-2,0)$ are given. There are also two points $P$ and $Q$ in the upper half-plane satisfying $\overline{AP} = \overline{OA}$, $\overline{BQ} = \overline{OB}$, $\angle POQ$ is a right angle. Let $\angle AOP = \theta$.
If $\sin\theta = \frac{3}{5}$, find the coordinates of point $Q$ and explain that $\overrightarrow{BQ} = 2\overrightarrow{AP}$. (Non-multiple choice question, 6 points)
taiwan-gsat 2023 Q20 6 marks Area Computation in Coordinate Geometry View
On the coordinate plane, $O$ is the origin, and points $A(1,0)$ and $B(-2,0)$ are given. There are also two points $P$ and $Q$ in the upper half-plane satisfying $\overline{AP} = \overline{OA}$, $\overline{BQ} = \overline{OB}$, $\angle POQ$ is a right angle. Let $\angle AOP = \theta$.
(Continuing from question 19, where $\sin\theta = \frac{3}{5}$) Find the distance from point $A$ to line $BQ$, and find the area of quadrilateral $PABQ$. (Non-multiple choice question, 6 points)
Given a vector $\vec { v } = ( - 2,3 )$ and two points $A$ and $B$ on the coordinate plane, where the $x$-coordinate and $y$-coordinate of point $A$, and the $x$-coordinate and $y$-coordinate of point $B$ all lie in the interval $[ 0,1 ]$, what is the maximum value of $| \vec { v } + \overrightarrow { A B } |$?
(1) $\sqrt { 13 }$
(2) $\sqrt { 17 }$
(3) $3 \sqrt { 2 }$
(4) 5
(5) $\sqrt { 2 } + \sqrt { 13 }$
taiwan-gsat 2024 Q15 5 marks Expressing a Vector as a Linear Combination View
Given that $P _ { 1 } , P _ { 2 } , Q _ { 1 } , Q _ { 2 } , R$ are five distinct points on a plane, where $P _ { 1 } , P _ { 2 } , R$ are not collinear, and satisfy $\overrightarrow { P _ { 1 } R } = 4 \overrightarrow { P _ { 1 } Q _ { 1 } }$ and $\overrightarrow { P _ { 2 } R } = 7 \overrightarrow { P _ { 2 } Q _ { 2 } }$, then $\overrightarrow { Q _ { 1 } Q _ { 2 } } =$ (15-1) $\overrightarrow { P _ { 1 } Q _ { 1 } } +$ (15-2)(15-3) $\overrightarrow { P _ { 2 } Q _ { 2 } }$.
taiwan-gsat 2024 Q16 5 marks Dot Product Computation View
On the coordinate plane, it is known that the orthogonal projection length of vector $\vec{v}$ in the direction of vector $(2, -3)$ is 1 less than its original length, and the orthogonal projection length in the direction of vector $(3, 2)$ is 2 less than its original length. If $\vec{v}$ makes acute angles with both vectors $(2, -3)$ and $(3, 2)$, then the orthogonal projection length of $\vec{v}$ in the direction of vector $(4, 7)$ is
taiwan-gsat 2025 Q9 5 marks Expressing a Vector as a Linear Combination View
On the coordinate plane, let $O$ be the origin and point $P$ have coordinates $( 2,2 )$ . Given that $\overrightarrow { O P } = \alpha \overrightarrow { O A } + \beta \overrightarrow { O B }$ , where real numbers $\alpha , \beta$ satisfy $0 \leq \alpha \leq 1,0 \leq \beta \leq 1$ . From the following options, select the possible coordinates of points $A$ and $B$.
(1) $A ( 2 , - 3 ) , B ( - 4,3 )$
(2) $A ( 3,2 ) , B ( 3,4 )$
(3) $A ( 3,4 ) , B ( 4 , - 1 )$
(4) $A ( 1,2 ) , B ( 2,1 )$
(5) $A ( 1 , - 1 ) , B ( 1,1 )$
taiwan-gsat 2025 Q11 6 marks Area and Geometric Measurement Involving Circles View
On the coordinate plane, there is a parallelogram $\Gamma$, where two sides lie on lines parallel to $5x - y = 0$, and the other two sides lie on lines perpendicular to $3x - 2y = 0$. Let $Q$ be the intersection point of the two diagonals of $\Gamma$. It is known that $\Gamma$ has a vertex $P$ satisfying $\overrightarrow{PQ} = (10, -1)$. The area of $\Gamma$ is (11--1)(11--2)(11--3).