Let $X : \Omega \rightarrow \mathbb{R}$ be a real-valued random variable. We assume that there exist two strictly positive reals $a$ and $b$ such that, for all non-negative reals $t$,
$$\mathbb{P}(|X| \geqslant t) \leqslant a \exp(-bt^{2})$$
Let $\delta$ be a real such that $0 \leqslant |\delta| \leqslant \sqrt{\frac{a}{b}}$. Justify that, for all reals $t$,
$$\mathbb{P}(|X + \delta| \geqslant t) \leqslant \mathbb{P}(|X| \geqslant t - |\delta|)$$
Let $X : \Omega \rightarrow \mathbb{R}$ be a real-valued random variable. We assume that there exist two strictly positive reals $a$ and $b$ such that, for all non-negative reals $t$,

$$\mathbb{P}(|X| \geqslant t) \leqslant a \exp(-bt^{2})$$

Let $\delta$ be a real such that $0 \leqslant |\delta| \leqslant \sqrt{\frac{a}{b}}$. Justify that, for all reals $t$,

$$\mathbb{P}(|X + \delta| \geqslant t) \leqslant \mathbb{P}(|X| \geqslant t - |\delta|)$$